Question

If $t_n$ denotes the nth term of the series $2+3+6+11+\mathrm{18...}$, then $t_{49}=$

• A. $2+{49}^2$
• B. $2+{48}^2$
• C. $2+{50}^2$
• D. $2+{51}^2$

Answer 1

The correct option is B $2+{48}^2$

given series is $2+3+6+11+\mathrm{18.....}$

$nth$ term of the series will be

$t_n=2+(n-1{)}^2$

so, $t_{49}=2+(49-1{)}^2$

$t_{49}=2+{48}^2$