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Question

If tn=sinnθ+cosnθ, then prove that t3t5t1=t5t7t3

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Solution

L.H.S. [(sin3θ+cos3θ)(sin5θ+cos5θ)]+(sinθ+cosθ)
=[sin3θ(1sin2θ)+cos3θ(1cos2θ)]+(sinθ+cosθ)
=sin2θcos2θ[sinθ+cosθ]+[sinθ+cosθ]
=sin2θcos2θ.
Similarly, R.H.S. =sin2θcos2θ.

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