If T r denotes the rth term in the expansion of x -1- y 23 thenA- T12-T13B- x2 T13-T12C- T12-x y T13D- T12-T13-25

The correct option is C T_12=^23C_11x^12 ( 1/y )^11=^23C_11x^12/y^11,T_13=^23C_11x^11 ( 1/y )^12 =^23C_11x^11/y^12,T_12=xy ( 23c_11x^11/y^12 )=xy T_13 ...

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Byju's Answer

Standard XI

Mathematics

Sum of product of binomial coefficients

If T r denote...

Question

If $T_{r}$ denotes the rth term in the expansion of ${(x + \frac{1}{y})}^{23}$ then

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Solution

The correct option is C

$T_{12} =^{23} C_{11} x^{12} {(\frac{1}{y})}^{11} =^{23} C_{11} \frac{x^{12}}{y^{11}}, T_{13} =^{23} C_{11} x^{11} {(\frac{1}{y})}^{12}$

$=^{23} C_{11} \frac{x^{11}}{y^{12}}, T_{12} = x y (23 c_{11} \frac{x^{11}}{y^{12}}) = x y T_{13}$

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If Tr denotes the rth term in the expansion of (x+1y)23 then

The correct option is C T12=23C11x12(1y)11=23C11x12y11,T13=23C11x11(1y)12 =23C11x11y12,T12=xy(23c11x11y12)=xy T13

If $T_{r}$ denotes the rth term in the expansion of ${(x + \frac{1}{y})}^{23}$ then

The correct option is C

$T_{12} =^{23} C_{11} x^{12} {(\frac{1}{y})}^{11} =^{23} C_{11} \frac{x^{12}}{y^{11}}, T_{13} =^{23} C_{11} x^{11} {(\frac{1}{y})}^{12}$

$=^{23} C_{11} \frac{x^{11}}{y^{12}}, T_{12} = x y (23 c_{11} \frac{x^{11}}{y^{12}}) = x y T_{13}$