If tall pea plant bearing red flowers is crossed with a short pea plant bearing white flowers. What will be the phenotypic ratio of $F_{2}$ generation?

3:1

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9:3:3:1

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9:2:3:2

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9:1:2:3

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Solution

The correct option is B 9:3:3:1
TR Tr tR tr
TR TTRR TTRr TtRR TtRr
Tr TTRr TTrr TtRr Ttrr
tR TtRR TtRr ttRR ttRr
tr TtRr Ttrr ttRr ttrr
Tall pea plant bearing red flowers - TTRR
Short pea plant bearing white flowers - ttrr
F1 generation - TtRr

Selfing of F1 - TtRr X TtRr
Gametes - TR,Tr, tR, tr TR, Tr, tR, tr
F2 generation:
9:3:3:1 is the phenotypic ratio.
9 Tall red : 3 Tall white: 3 Dwarf red: 1 Dwarf white

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	TR	Tr	tR	tr
TR	TTRR	TTRr	TtRR	TtRr
Tr	TTRr	TTrr	TtRr	Ttrr
tR	TtRR	TtRr	ttRR	ttRr
tr	TtRr	Ttrr	ttRr	ttrr

If tall pea plant bearing red flowers is crossed with a short pea plant bearing white flowers. What will be the phenotypic ratio of F2 generation?

If tall pea plant bearing red flowers is crossed with a short pea plant bearing white flowers. What will be the phenotypic ratio of $F_{2}$ generation?