If tan-1tan5-4- and tan-1 - tan2-3- then-

The correct option is B α +β =7π/12 tan^ 1 ( tan #160; 5π #160; 4 )=α ⇒ 5π #160; 4 =α Also, tan^ 1 ( tan #160; 2π #160; 3 ...

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Basic Inverse Trigonometric Functions

If tan-1tan...

Question

If ${tan}^{- 1} (tan \frac{5 π}{4}) = α$ and ${tan}^{- 1} (- tan \frac{2 π}{3}) = β$ then.

α - β = \frac{7 π}{12}

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α + β = \frac{7 π}{12}

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2 α + 3 β = \frac{7 π}{12}

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4 α + 3 β = \frac{7 π}{12}

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= \frac{1}{2}

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α

β

| α | + | β - 1 | = | α - 1 | + | β |,

| α + β |

{(\frac{5 π}{12})}^{\circ}

- {(\frac{7 π}{12})}^{\circ}

\frac{π}{3}

\frac{5 π^{\circ}}{6}

\frac{2 π^{\circ}}{9}

\frac{7 π^{\circ}}{24}

\begin{matrix} X = sin (θ + \frac{7 π}{12}) + sin (θ - \frac{π}{12}) + sin (θ + \frac{3 π}{12}), Y = cos (θ - \frac{7 π}{12}) + cos (θ - \frac{π}{12}) + cos (θ + \frac{3 π}{12}) p r o v e t h a t \frac{x}{y} - \frac{y}{x} = 2 tan 2 θ . \end{matrix}

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