If tan-1x-tan-1y-4- xy - 1- then write value of x-y-xy-

tan^ 1x+tan^ 1y=tan^ 1x+y1 xy=π4 Therefore, x+y1 xy=tanπ4 x+y1 xy=1 x+y=1 xy x+y+xy=1 ...

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Theorems on Integration

If tan-1x+t...

Question

If $t a n^{- 1} x + t a n^{- 1} y = \frac{π}{4}, x y < 1$ , then write value of $x + y + x y$ .

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{s i n}^{- 1} x, {c o s}^{- 1} x, {t a n}^{- 1} x

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