If tan2 30- -tan2 45- -tan2 60- is m1-3- then m is-

tan^2 30^∘ + tan^2 45^∘ + tan^2 60^∘ = (1√(3))^2 + 1^2 + (√(3))^2 = 13 + 1 + 3 = 1 + 3 + 93 = 133 = 4 13 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

First Principle of Differentiation

If tan2 30∘...

Question

If ${tan}^{2} 30^{\circ} + {tan}^{2} 45^{\circ} + {tan}^{2} 60^{\circ}$ is $m \frac{1}{3}$ , then $m$ is:

Open in App

Solution

Suggest Corrections

Similar questions

t a n^{2} 30^{\circ} + t a n^{2} 60^{\circ} + t a n^{2} 45^{\circ}

Evaluate each of the following

$t a n^{2} 30^{o} + t a n^{2} 60^{o} + t a n^{2} 45^{o}$

\frac{x {cosec}^{2} 30 ° \sec^{2} 45 °}{8 \cos^{2} 45 ° \sin^{2} 60 °} = \tan^{2} 60 ° - \tan^{2} 30 °

{cos}^{2} 60^{\circ} + {sec}^{2} 30^{\circ} + {tan}^{2} 45^{\circ}

m \frac{7}{12}

m

Join BYJU'S Learning Program