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Question

If tan2θ=cot(θ+6), where 2θ and θ+6 are acute angles, find the value of θ.

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Solution

Given 2θ,θ+6 are acute angles

tan2θ=cot(θ+6)

tan2θ=tan(90θ6)

2θ=84θ

3θ=84

θ=28

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