If tan2-tan2-Then P-T 1-tan 2 - 1-tan 2 - - 1-tan 2 - 1-tan 2 -

Given tan^2θ=tan^2α LHS= 1 tan ^ 2 θ #160; #160; 1+tan ^ 2 θ #160; #160; = 1 tan ^ 2 α #160; #160; 1+tan ^ 2 α #160; #160; # ...

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Trigonometric Identities

If tan2θ=ta...

Question

If ${tan}^{2} θ = {tan}^{2} α$ '
Then P.T $\frac{1 - {tan}^{2} θ}{1 + {tan}^{2} θ} = \frac{1 - {tan}^{2} α}{1 + {tan}^{2} α}$

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