If tan3θ+cot3θ=2, then which of the following is/are correct?
A
sinθ=−secθ
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B
sinθ=−cosθ
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C
2sinθ=secθ
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D
2sinθ=cosθ
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Solution
The correct option is C2sinθ=secθ tan3θ+cot3θ=2 Assuming tan3θ=t, so t+1t=2⇒t2−2t+1=0⇒(t−1)2=0⇒t=1⇒tan3θ=1∴tanθ=1 Now, sinθ=1√2 and cosθ=1√2 Therefore, 2sinθ=secθ