wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If tan π/4+θ+ tan π/4-θ=λ sec 2 θ, then λ=
(a) 3
(b) 4
(c) 1
(d) 2

Open in App
Solution

(d) 2

Given: tanπ4+θ+tanπ4-θ=λ sec 2θtanπ4+tanθ1-tanπ4×tanθ+tanπ4-tanθ1+tanπ4×tanθ=λ sec 2θ1+tanθ1-tanθ+1-tanθ1+tanθ=λ sec 2θ1+tanθ2+1-tanθ21-tanθ1+tanθ=λ sec 2θ21+tan2θ1-tan2θ=λ sec 2θ

2sec2θ1-tan2θ=λ sec 2θ2cos2θ1-tan2θ=λ sec 2θ2cos2θ1-sin2θcos2θ=λ sec 2θ2cos2θ-sin2θ=λ sec 2θ2cos2θ=λ sec 2θ2sec2θ=λ sec 2θ2=λ λ=2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Property 5
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon