If tan A = 0.8021, then find the value of A. (Given: tan 38° 42′ = 0.8012, tan 38° 48′ = 0.8040 and mean difference for 2' = 9.)

38°41'

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38°42'

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38°43'

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38°44'

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Solution

The correct option is D 38°44'
Given: tan A = 0.8021, tan38°42' = 0.8012 and tan38°48' = 0.8040

tan38°42' = 0.8012
+ 9
____________________
0.8021
So, mean difference value = 9
9 corresponds to 2'.
So, A = 38°42' + 2' = 38°44'

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If tan A = 0.8021, then find the value of A. (Given: tan 38° 42′ = 0.8012, tan 38° 48′ = 0.8040 and mean difference for 2' = 9.)

The correct option is D 38°44'Given: tan A = 0.8021, tan38°42' = 0.8012 and tan38°48' = 0.8040 tan38°42' = 0.8012 + 9 ____________________ 0.8021 So, mean difference value = 9 9 corresponds to 2'. So, A = 38°42' + 2' = 38°44'

The correct option is D 38°44'
Given: tan A = 0.8021, tan38°42' = 0.8012 and tan38°48' = 0.8040

tan38°42' = 0.8012
+ 9
____________________
0.8021
So, mean difference value = 9
9 corresponds to 2'.
So, A = 38°42' + 2' = 38°44'