wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If tanA and tanB are the roots of the quadratic equation, 3x210x25=0, then the value of 3sin2(A+B)10sin(A+B)cos(A+B)25cos2(A+B) is :

A
10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
25
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
25
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 25
3x210x25=03x215x+5x25=0(3x+5)(x5)=0x=53, 5
Now,
tan(A+B)=tanA+tanB1tanAtanB =5531+253=514cos(A+B)=14221
Now,
S=3sin2(A+B)10sin(A+B)cos(A+B)25cos2(A+B)S=cos2(A+B)[3tan2(A+B)10tan(A+B)25]S=196221[3×2519610×51425]S=25221[328196]S=25

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relation of Roots and Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon