If tan(A+B)=√3 and tan A=1 then find angle B

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Solution

Given,
tan(A+B)= √3. ---(1)
tan A= 1. ---(2)

We know,
tan 60°=√3.
So from (1), A+B= 60°

Now tan 45°=1.
So from (2) we get A=45°

A+B=60°. equation-(3)
A=45° . equation-(4)
Sofrom (3) and (4)
we get

B=15°

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If tan(A+B)=√3 and tan A=1 then find angle B

Given, tan(A+B)= √3. ---(1) tan A= 1. ---(2) We know, tan 60°=√3. So from (1), A+B= 60° Now tan 45°=1. So from (2) we get A=45° A+B=60°. equation-(3) A=45° . equation-(4) Sofrom (3) and (4) we get B=15° ​​​​​​

Given,
tan(A+B)= √3. ---(1)
tan A= 1. ---(2)

We know,
tan 60°=√3.
So from (1), A+B= 60°

Now tan 45°=1.
So from (2) we get A=45°

A+B=60°. equation-(3)
A=45° . equation-(4)
Sofrom (3) and (4)
we get

B=15°