If tanA-B-p- tanA-B-q then prove that tan2A-p-q1-pq-

tan 2A = tan[ ( A + B) + ( A B)] = tan( A + B) + tan( A B)1 tan( A + B)tan( A B) = p + q1 pq ...

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Sin(A+B)Sin(A-B)

If tanA+B=p...

Question

If $tan (A + B) = p, tan (A - B) = q$ then prove that $tan 2 A = \frac{p + q}{1 - p q}$ .

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