Question

If $\tan A=\frac{5}{12}$, then the value of $(\sin A+\cos A)\sec A$ is ______ .

Answer 1

REF.Image.

Given $tanA=\frac{5}{12}$

$\therefore SinA=\frac{5}{13}$

$cosA=\frac{12}{13}$

$secA=\frac{13}{12}$

$(sinA+cosA)secA=(\frac{5}{13}+\frac{12}{13})\times \frac{13}{12}$

$=\frac{17}{13}\times \frac{13}{12}$

$\therefore (sinA+cosA)secA=\frac{17}{12}$