If tan A = cot B, prove that $A + B = 90^{\circ}$ .

Open in App

Solution

According to question,
tan A = cot B
$\Rightarrow t a n A = t a n (90^{\circ} - B)$
$\Rightarrow A = 90^{\circ} - B$
$\Rightarrow A + B = 90^{\circ}$

Suggest Corrections

Similar questions

If tan A = cot B, prove that A + B = 90°

tan A = cot B,

A + B = 90^{\circ} .

t a n A = cot B,

A + B = 90^{0}

A + B = 90^{\circ}

t a n A = c o t B

A + B = 90^{\circ}

Join BYJU'S Learning Program