If tan A-135-tan B-1817- then tan A-B-

The correct option is A tan 45^o tan A = 1/35 #160; #160; #160; #160; tan B = 18/17 tan (A A) = tan A tan B/1+tanA tanB = 1/35 ...

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Byju's Answer

Standard XII

Mathematics

Trigonometric Equations

If tan A=13...

Question

If $tan A = \frac{1}{35} . tan B = \frac{18}{17}$ , then $tan (A - B)$ =

tan 45^{o}

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Solution

The correct option is A $tan 45^{o}$
$t a n A = \frac{1}{35} t a n B = \frac{18}{17}$

$t a n (A - A) = \frac{t a n A - t a n B}{1 + t a n A t a n B}$

$= \frac{\frac{1}{35} - \frac{- 18}{17}}{1 + (\frac{1}{35}) (\frac{18}{17})}$

$= \frac{17 - 18 (35)}{(35) (17) + (18)}$

$= \frac{17 - 630}{(595) + 18} = \frac{- 613}{613} = - 1$

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If tanA=135.tanB=1817, then tan(A−B)=

The correct option is A tan45otanA=135tanB=1817tan(A−A)=tanA−tanB1+tanAtanB=135−−18171+(135)(1817)=17−18(35)(35)(17)+(18)=17−630(595)+18=−613613=−1

If $tan A = \frac{1}{35} . tan B = \frac{18}{17}$ , then $tan (A - B)$ =