Question

If $\tan A=\frac{3}{4}$ and $A+B={90}^0$, then find the value of $\cot B$.

• A. $\frac{3}{4}$
• B. $-\frac{4}{3}$
• C. $-\frac{3}{4}$
• D. $\frac{4}{3}$

Answer 1

The correct option is A $\frac{3}{4}$

$A+B={90}^o$
$A=90-B$

fake tan Both side

$\tan A=\tan (90-B)$

$\tan A=\cot B$

$\cot B=3/4$