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Question

If tanA=xsinB1xcosB and tanB=ysinA1ycosA then sinAsinB=

A
xy
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B
yx
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C
x+y
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D
xy
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Solution

The correct option is A xy
sinAcosA=xsinB1xcosBsinAxsinAcosB=xcosAsinBsinA=xsin(A+B)
Similarly sinB=ysin(A+B).sinAsinB=xy.

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