Question

If $\tan A$ position two short bar magnets of magnetic moments in ratio of $\sqrt{3}:1$ are placed at same distance respectively. If the deflection produced for the first magnet be ${60}^o$ then what will be deflection for second magnet?

Answer 1

The magnetic field is given as,

$B=B_E\tan \theta$

$\frac{{\mu }_0}{4\pi }\times \frac{2M}{r^2}=B_E\tan \theta$

$M\propto \tan \theta$

The ratio of magnetic moments is given as,

$\frac{M_1}{M_2}=\frac{\tan {60}^{\circ }}{\tan \theta }$

$\frac{\sqrt{3}}{1}=\frac{\sqrt{3}}{\tan \theta }$

$\theta ={45}^{\circ }$

Thus, the deflection for second magnet is ${45}^{\circ }$.