If tan A - 3 and tan B - 1 - 3 - then value of tan A-B will be-

The correct option is D None of these tan(A+B) = tanA+tanB1 tanAtanB #160; #160; #160; #160; #160; #160; #160; #160; #160; #1 ...

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Standard XII

Mathematics

Conditional Identities

If tan A =√...

Question

If $tan A = \sqrt{3}$ and $tan B = \frac{1}{\sqrt{3}}$ , then value of $tan (A + B)$ will be:

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Solution

The correct option is D None of these
$t a n (A + B) = \frac{t a n A + t a n B}{1 - t a n A t a n B}$
$= \frac{\sqrt{3} + \frac{1}{\sqrt{3}}}{1 - \frac{\sqrt{3}}{\sqrt{3}}}$
$= \frac{\sqrt{3} + \frac{1}{\sqrt{3}}}{1 - 1}$
$= \infty$

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If tanA=√3 and tanB=1√3, then value of tan(A+B) will be:

The correct option is D None of thesetan(A+B)=tanA+tanB1−tanAtanB =√3+1√31−√3√3 =√3+1√31−1 =∞

If $tan A = \sqrt{3}$ and $tan B = \frac{1}{\sqrt{3}}$ , then value of $tan (A + B)$ will be:

The correct option is D None of these
$t a n (A + B) = \frac{t a n A + t a n B}{1 - t a n A t a n B}$
$= \frac{\sqrt{3} + \frac{1}{\sqrt{3}}}{1 - \frac{\sqrt{3}}{\sqrt{3}}}$
$= \frac{\sqrt{3} + \frac{1}{\sqrt{3}}}{1 - 1}$
$= \infty$