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Question

If tanA,tanB are the roots of the quadratic ab x2c2x+ab=0, where a,b,c are the sides of a triangle, then prove
cosC=0

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Solution

abx2c2x+ab=0
α=tanA,β=tanB
α+β=tanA+tanB=c2ab
tanAtanB=abab=1
tan(A+B)=tanA+tanB1tanAtanB
tan(A+B)=c2ab11
tan(A+B)=
A+B=π2
Given,A+B+C=π
C=π2
cosC=0

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