If tan A - tan B are the roots of x 2- P x - Q -0 the value of sin 2 A - B - where P - Q - R P2-P-Q2B- P2-P2-Q2C- Q2-P2-1-Q2D- P2-P2-1-Q2

The correct option is D tan (A+B)=P/1 Q then sin^2 (A+B)=tan^2 (A+B)/1+tan^2 (A+B) ...

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Trigonometric Ratios for Sum of Two Angles

If tan A , ta...

Question

If tan A, tan B are the roots of $x^{2} - P x + Q = 0$ the value of $s i n^{2}$ (A+B)=(where P, Q $ϵ$ R)

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Similar questions

If tan A, tan B are the roots of $x^{2} - P x + Q = 0$ the value of $s i n^{2}$ (A+B)=(where P, Q $ϵ$ R)

t a n A, t a n B

x^{2} - p x + q = 0

s i n^{2} (A + B)

tan a, tan b

x^{2} - p x + q = 0

cot a, cot b

x^{2} - r x + s = 0

r s

x^{2} + p x + q = 0

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