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B
the sum of any two of A,B,C is equal to the third
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C
A+B+C must be n integral multiple of π
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D
None of these
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Solution
The correct option is C A+B+C must be n integral multiple of π If A+B+C=π ⇒tan(A+B+C)=tanπ ⇒tanA+tanB+tanC−tanAtanBtanC1−tanAtanB−tanBtanC−tanAtanC=0 ⇒tanA+tanB+tanC−tanAtanBtanC=0