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Question

If tanA+tanB+tanC=tanA.tanB.tanC, then

A
A,B,C must be angles of a triangle
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B
the sum of any two of A,B,C is equal to the third
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C
A+B+C must be n integral multiple of π
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D
None of these
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Solution

The correct option is C A+B+C must be n integral multiple of π
If A+B+C=π
tan(A+B+C)=tanπ
tanA+tanB+tanCtanAtanBtanC1tanAtanBtanBtanCtanAtanC=0
tanA+tanB+tanCtanAtanBtanC=0

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