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Question

If tanα+cotα=p where p2, then the value of tanαcotα is

A
p34
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B
4p24
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C
p22
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D
p24
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Solution

The correct option is D p24
Let tanαcotα=x

Squaring, tan2α+cot2α2tanαcotα=x2 .... (1)

Given tanα+cotα=p

Squaring, tan2α+cot2α+2tanαcotα=p2

tan2α+cot2α=p22 ...(tanαcotα=1)

Put in (1), we get
p222=x2x=p24

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