If tan-tan-m and -n- then prove that -1m-1n

tan (α β ) =tanα #160; tanβ #160; #160; / 1+tanα #160; tanβ #160; #160; (α β ) = 1+tanα #160; tanβ #160; #160; /tanα #16 ...

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If tanα-tan...

Question

If $tan α - tan β = m$ and $cot α - cot β = n$ , then prove that $cot (α - β) = \frac{1}{m} - \frac{1}{n}$

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tan α = \frac{m}{m + 1}

tan β = \frac{1}{2 m + 1}

α + β = \frac{π}{4}

tan α = \frac{m}{m + 1}

tan β = \frac{1}{2 m + 1}

α + β =

α

β

tan α = \frac{m}{m + 1}

tan β = \frac{1}{2 m + 1}

α + β = \frac{π}{m}

tan α = m / (m + 1), tan β = 1 / (2 m + 1)

α + β = π / 4

t a n α = \frac{m}{m + 1}

t a n β = \frac{1}{2 m + 1}

(α + β)

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