If tan-5- then tan 2- 2- -a 23b 24c 25d 27

(d) 23 We have (tan theta; +cot theta;) = 5 Squaring both sides, we get: (tan theta; +cot theta;)2 = 52 rArr; tan2 theta; + cot2 theta; + 2 ...

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Composition of Trigonometric Functions and Inverse Trigonometric Functions

If tanθ+θ=5, ...

Question

If (tan θ + cot θ) = 5, then (tan² θ + cot² θ) = ?

(a) 23
(b) 24
(c) 25
(d) 27

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If (tan $θ$ + cot $θ$ ) = 5 then ( $t a n^{2} θ$ + $c o t^{2} θ$ ) = ?

(a) 27 (b) 25 (c) 24 (d) 23

\frac{1}{\sqrt{7}}

\frac{(\cos e c^{2} θ - s e c^{2} θ)}{(\cos e c^{2} θ + s e c^{2} θ)} = ?

\frac{- 2}{3}

\frac{- 3}{4}

\frac{2}{3}

\frac{3}{4}

tan θ + cot θ = 5,

{tan}^{2} θ + {cot}^{2} θ

θ -

\frac{(1 + {tan}^{2} θ)}{{csc}^{2} θ} = tan θ

\frac{tan θ - cot θ}{sin θ cos θ} = {tan}^{2} θ - {cot}^{2} θ

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