If tanB-C-2-x A-2- thenx -

The correct option is C b c/b + ctan B C/2 = x cot A/2⇒ x = b c/b+c. ...

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Napier’s Analogy

If tanB-C/2=x...

Question

If $t a n \frac{B - C}{2} = x c o t \frac{A}{2}, t h e n x =$

\frac{c - a}{c + a}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{a - b}{a + b}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{b - c}{b + c}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

t a n \frac{B - C}{2} = x c o t \frac{A}{2}, t h e n x =

I n △ A B C, i f x = tan (\frac{B - C}{2}) tan \frac{A}{2}, y = tan (\frac{C - A}{2}) tan \frac{B}{2}, z tan (\frac{A - B}{2}) tan \frac{C}{2}, t h e n x + y + z

If $A + B + C = π$ then, $tan \frac{A}{2} \cdot tan \frac{B}{2} + tan \frac{B}{2} \cdot tan \frac{C}{2} + tan \frac{C}{2} \cdot tan \frac{A}{2}$ =

\frac{c}{a - b} = \frac{tan \frac{A}{2} + tan \frac{B}{2}}{tan \frac{A}{2} - tan \frac{B}{2}}

Δ A B C

\frac{b - c}{b + c} = \frac{tan (\frac{B - C}{2})}{tan (\frac{B + C}{2})}

Join BYJU'S Learning Program