If $tan (A + B) = x$ and $tan (A - B) = y$ find the value of $tan 2 A$ .

Open in App

Solution

$tan (A + B) = x$ and $tan (A - B) = y$
Now, $tan 2 A = t a n [(A + B) + (A - B)]$
$= \frac{tan (A + B) + tan (A - B)}{1 - tan (A + B) tan (A - B)}$
$= \frac{x + y}{1 - x y}$

Suggest Corrections

Similar questions

tan (A + B) = x

t a n (A - B) = y

tan 2 A

tan 2 B

tan A - \frac{1}{tan A} = \sqrt{2}

{tan}^{2} A + \frac{1}{{tan}^{2} A}

tan A - tan B = x

cot B - cot A = y

cot (A - B)

Find the value of tan 3A in terms of tanA & tan2A

Join BYJU'S Learning Program