If tan-17- then cosec 2 - 2 -cosec 2 - 2 -a 57b 37c 112d 34

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Value of Standard Angle(30,60,90)

If tanθ=17, t...

Question

If $\tan θ = \frac{1}{\sqrt{7}}, then \frac{{cosec}^{2} θ - \sec^{2} θ}{{cosec}^{2} θ + \sec^{2} θ} =$

(a) $\frac{5}{7}$
(b) $\frac{3}{7}$
(c) $\frac{1}{12}$
(d) $\frac{3}{4}$

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Solution

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\frac{1}{\sqrt{7}}

(\frac{{cosec}^{2} θ + \sec^{2} θ}{{cosec}^{2} θ - \sec^{2} θ}) = \frac{4}{3} .

tanθ = \frac{1}{\sqrt{7}}

\frac{{cosec}^{2} θ - \sec^{2} θ}{{cosec}^{2} θ + \sec^{2} θ}

tan θ = \frac{1}{\sqrt{7}}

\frac{{cosec}^{2} θ - {sec}^{2} θ}{{cosec}^{2} θ + {sec}^{2} θ} = . . . . . .

tan θ = \frac{1}{\sqrt{3}}

\frac{cos e c^{2} θ - {sec}^{2} θ}{cos e c^{2} θ + {sec}^{2} θ}

\cot θ = \sqrt{3}

\frac{\cos e c^{2} θ + \cot^{2} θ}{{cosec}^{2} θ - \sec^{2} θ}

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