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Sign of Trigonometric Ratios in Different Quadrants

If tan θ=3 an...

Question

$If tan θ = \sqrt{3} and sin θ = \frac{- \sqrt{3}}{2}, then' θ' lies in the second quadrant .$

A

False

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B

True

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Solution

The correct option is A False

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θ

lies in the first quadrant and

5 tan θ = 4

\frac{5 sin θ - 3 cos θ}{sin θ + 2 cos θ}

θ

lies in the second quadrant, then the value of

\sqrt{(\frac{1 - sin θ}{1 + sin θ})} + \sqrt{(\frac{1 + sin θ}{1 - sin θ})}

sin θ = \frac{2 t}{1 + t^{2}}

θ

lies in the second quadrant, then

cos θ

θ

lies in the second quadrant, then the value of

\sqrt{(\frac{1 - sin θ}{1 + sin θ})} + \sqrt{(\frac{1 + sin θ}{1 - sin θ})}

tan θ = \sqrt{3}

and 'θ' lies in the third quadrant, then

sin θ + cos θ

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Sign of Trigonometric Ratios in Different Quadrants

Standard XIII Mathematics

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