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Question

If tanθ+3cotθ=5secθ then θ=

A
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Solution

The correct option is B
tanθ+3cotθ=5secθsin2θ+3 cos2θ=5sinθsin2θ+3(1sin2θ)=5 sin θ(sin θ+3)(2 sin θ1)=0sin θ=3 or 12sin θ=12θ=nπ+(1)nπ6,nϵZ.

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