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Question

If tanθ+cotθ=5, then tan2θ+cot2θ=

A
27
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B
29
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C
24
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D
23
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Solution

The correct option is D 23
tanθ+cotθ=5
(tanθ+cotθ)2=52, square both sides
tan2θ+2tanθcotθ+cot2θ=25
tan2θ+cot2θ+2=25(tanθcotθ=1)
tan2θ+cot2θ=23

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