If tan- -1tan-2- then show that tan2- -1tan2-2-

tanθ + 1tanθ = 2 (tanθ + 1tanθ)^2 = 4 tan^2 θ + 1tan^2 θ + 2 = 4 tan^2 θ + 1tan^2 θ = 2 Hence proved. ...

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Relationship between Trigonometric Ratios

If tanθ +1t...

Question

If $tan θ + \frac{1}{tan θ} = 2$ , then show that ${tan}^{2} θ + \frac{1}{{tan}^{2} θ} = 2$ .

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t a n Θ + \frac{1}{t a n Θ} = 2,

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$If t a n θ + c o t θ = 2,$ then $t a n^{2} θ + c o t^{2} θ$ = _____.

tan θ = \frac{1}{2}

tan ϕ = \frac{1}{3}

tan (2 θ + ϕ)

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