Question

If $tan\theta =\frac{5}{12},,2nd\theta$ is acute angle.Then the value of $sec\theta +cosec\theta$

Answer 1

$tan\theta =\frac{P}{B}=\frac{5k}{12k}\Rightarrow H=\sqrt{(5k{)}^2+(12k^2)}=\sqrt{169k^2}=13k$

$\Rightarrow sec\theta =\frac{H}{B}=\frac{13k}{12k}=\frac{13}{12};cosec\theta =\frac{H}{P}=\frac{13k}{5k}=\frac{13}{5}$