wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If tanθ=ab, then asinθbcosθasinθ+bcosθ=.....

A
a2+b2a2b2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a2b2a2+b2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
a2a2+b2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
b2a2+b2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B a2b2a2+b2
Dividing numerator and denominator by cosθ we get
(asinθbcosθ)(asinθ+bcosθ)=atanθbatanθ+b=a×abba×ab+b=a2b2a2+b2

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Trigonometric Identities_Concept
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon