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Question

If tan θ =815 then cosec θ = ?

(a) 178 (b) 817 (c) 1715 (d) 1517

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Solution

tanA=815=perpendicularbase

perpendicular=8x,base=15x

hypotenuese=(15x)2+(8x)2=225x2+64x2=289x2=17x

cosecA=hypotenueseperpendicular=17x8x=178


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