If tan- - y-x- the value x-x2 - y23-2 will be when expressed in terms of x and -

Given : #160; #160; #160; y = xtanθ So, #160; #160; #160; x(x^2+y^2)^3/2 = x(x^2 + x^2tan^2θ)^3/2 #160; #160; #160; #160; #160; ...

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Tangent, Cotangent, Secant, Cosecant in Terms of Sine and Cosine

If tanθ = y...

Question

If $tan θ = \frac{y}{x}$ , the value $\frac{x}{(x^{2} + y^{2})^{3 / 2}}$ will be when expressed in terms of x and $θ$

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secθ + tanθ = x

tanθ =

\frac{x^{2} + 1}{x}

\frac{x^{2} - 1}{x}

\frac{x^{2} + 1}{2 x}

\frac{x^{2} - 1}{2 x}

$\frac{t a n θ}{s e c θ}$ + $\frac{c o t θ}{c o s e c θ}$ in terms of $s i n θ$ and $c o s θ$ (if $s i n θ$ = x and $c o s θ$ = y) can be written as:

x = \sqrt{{cos}^{2} θ + \sqrt{{cos}^{2} θ {\sqrt{cos}}^{2} θ + . . . \infty}}

y = \sqrt{sec θ - \sqrt{sec θ - \sqrt{sec θ - . . . \infty}}}

(x^{2} - x) (y^{2} + y) = 1

z = \sqrt{tan θ + \sqrt{tan θ + \sqrt{tan θ + . . . \infty}}}

z^{2} = tan θ + z

\frac{{(x^{2} {- y}^{2})}^{3} + {(y^{2} - z^{2})}^{3} + {(z^{2} - x^{2})}^{3}}{{(x - y)}^{3} + {(y - z)}^{3} + {(z - x)}^{3}}

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