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Question

If tanθ+secθ=2x then prove that secθ=x+14x.

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Solution

Given,
tanθ+secθ=2x......(1).
We've,
sec2θtan2θ=1
or, (secθtanθ)(secθ+tanθ)=1
or, secθtanθ=12x......(2) [ Using (1)].
Now, adding (1) and (2) we get,
2secθ=2x+12x
or, secθ=x+14x.

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