Question

If $\tan \theta =\sqrt{3}$ then the number of solutions for $\theta$ if $0\le \theta \le {360}^0$ is:

Answer 1

Given that,

$\tan \theta =\sqrt{3}$

i.e., $\tan {60}^{\circ }=\sqrt{3}$ and $\tan {240}^{\circ }=\sqrt{3}$

$\therefore \theta ={60}^{\circ }$ and $\theta ={240}^{\circ }$

The number of solutions for $\theta =2$