Question

If $\tan \theta =\sqrt{3}$ (where $\theta$ is acute), then find the value of $1+\cos \theta$.

Answer 1

Given $\tan \theta =\sqrt{3}$ and $\theta$ is acute

Now $\theta$ lies in first quadrant, so value of $\theta$ will be ${60}^o$.

Now value of $1+\cos \theta =1+\cos 60=1+\sqrt{3}/2$