Question

If $\tan \theta =\tan {240}^o$, then the value of $\theta$ in the first quadrant is ${30}^o$.

• A. True
• B. False

Answer 1

The correct option is B False

$\tan \theta =\tan {240}^{\circ }=\tan (180+60)=\tan 60=\tan (90-{30}^{\circ })=\cot {30}^{\circ }$

$\tan \theta =\cot {30}^{\circ }=\tan {60}^{\circ }$

$\therefore \theta ={60}^{\circ }$