Question

If $\tan \theta +\tan 4\theta +\tan 7\theta =\tan \theta \tan 4\theta \tan 7\theta$, then the general solution is?

• A. $\theta =\frac{n\pi }{4}$
• B. $\theta =\frac{n\pi }{12}$
• C. $\theta =\frac{n\pi }{6}$
• D. None of these

Answer 1

The correct option is B $\theta =\frac{n\pi }{12}$

we know, that

$tanA+tanB+tanC=tanA.tanB.tanC$ if $A+B+C=n\pi$

Hence, $12\theta =n\pi$

$\theta =\frac{n\pi }{12}$