Given: tan 2A = cot (A - 18∘) On rearranging the equation with one trigonometric ratio on each side, we get
⇒ tan 2A = tan (90 - (A - 18∘)) ∵tan(90°−θ)=cotθ
⇒ tan 2A = tan (108∘ - A)
⇒ 2A = 108∘ - A ⇒ 3A = 108∘
⇒ A = 36∘
If tan 2A = cot (A - 18o), then the value of A is
If tan2A=cot(A−18∘), then value of A is ((A - 18) & 2A are acute angle)