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Question

If tanA =5/12 the value of (sinA+cosA)swcA

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Solution

Consider, (sinA + cosA) × secA
= (sinA + cosA)/cosA
= (sinA/cosA + cosA/cosA)
= tanA + 1
= (5/12) + 1 [Given tanA = 5/12]
= 17/12

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