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Question

If tangents are drawn from a point P(2,0) to the curve 1+y2=x3 which meet the curve at A and B, then

A
PAB is equilateral
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B
AB=5
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C
acute angle between the tangents is tan1(52)
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D
area of PAB is 554 sq. units
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Solution

The correct option is D area of PAB is 554 sq. units

1+y2=x3
Differentiating w.r.t. x,
2y21+y2(dydx)=13
dydx=1+y23y
dydx(h,k)=1+k23k
k0h2=1+k23k
3k2h2=1+k2
3(h291)h2=h3
h29h2=h
h29=h22h
h=92
So, k=±52

Let AP make angle θ with xaxis in anticlockwise direction.
Then, acute angle between the tangents is 2θ.
Slope of AP is tanθ=15
tan2θ=2tanθ1tan2θ=52
2θ=tan1(52)

AB=5

Area of PAB is 12×5×(922)=554

APAB
Hence, PAB is not equilateral.


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