If m1 - 6 kg- m2 - 2 kg and m3 - 4 kgWe can say about m1 as

Let a be acceleration wrt small pulley For system of 2 kg and 4 kg as shown 40 20 = 6a ⇒ a=20/6 40 T=4a ⇒ T=80/3 So 2T lt;m_1g ⇒ block m_1 will accelerate ...

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Byju's Answer

Standard XII

Physics

Constrained Motion : General Approach

If m1 = 6 kg,...

Question

If  $m_{1}$ = 6 kg, $m_{2}$ = 2 kg and $m_{3}$ = 4 kg
We can say about $m_{1}$ as

Acceleration of

m_{1}

will be zero.

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Acceleration of

m_{1}

will be upwards.

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Acceleration of

m_{1}

will be downwards.

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m_{1}

may accelerate upwards or downwards.

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Solution

The correct option is C

Acceleration of $m_{1}$ will be downwards.
let $a$ be acceleration wrt small pulley
For system of 2 kg and 4 kg as shown
$40 - 20 = 6 a \Rightarrow a = \frac{20}{6}$
$40 - T = 4 a \Rightarrow T = \frac{80}{3}$

So $2 T < m_{1} g \Rightarrow$ block $m_{1}$ will accelerate downwards.

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If  m1 = 6 kg, m2 = 2 kg and m3 = 4 kg We can say about m1 as

The correct option is C Acceleration of m1 will be downwards.let a be acceleration wrt small pulley For system of 2 kg and 4 kg as shown 40−20=6a⇒a=206 40−T=4a⇒T=803 So 2T<m1g⇒ block m1 will accelerate downwards.

If  $m_{1}$ = 6 kg, $m_{2}$ = 2 kg and $m_{3}$ = 4 kg
We can say about $m_{1}$ as