if temperature remain constant and the current I through a resistor is doubled,then the increase in power dissipated will be :

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Solution

Dear Student,

$f o r c o n s \tan t t e m p P = I^{2} R f r o m t h e a b o v e e q n w e c a n e a s i l y s e e t h a t t h e p o w e r i s d i r e c t l y p r o p o r t i o n a l t o t h e s q u a r e o f c u r r e n t . i f c u r r e n t i s d o u b l e t h e n t h e p o w e r b e c o m e s f o u r t i m e s . R e g a r d s$

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if temperature remain constant and the current I through a resistor is doubled,then the increase in power dissipated will be :

Dear Student, for constant temp P=I2Rfrom the above eqn we can easily see that the power is directly proportional to the square of current .if current is double then the power becomes four times.Regards