Let a, b, c be complex such that ab+bc+ca=12,(a+b+c)=2,abc=4 then the value of 1ab+c−1+1bc+a−1+1ac+b−1 is
If ΔABC≅ΔDEF, AB = 5 cm, BC = 6 cm, AC = 7 cm, then the length of EF is: